Giả sử $n_{{MO}_{pu}}=1$ (mol)
$MO+H_{2}SO_{4}\rightarrow MSO_{4}+H_{2}O$ $1$ $\rightarrow$ $1$ $\rightarrow$ $1$ (mol)
$m_{ddH_{2}SO_{4}}= \frac{98.1.100}{17,5}=560$ (g)
Ta có: $\frac{M+96}{M+16+560}.100=20$
$\rightarrow \frac{M+96}{M+576}.100=20$
$\rightarrow M$ là $magie$ $(Mg=24)$
Chúc bạn học tốt! ^^