2Goi CT chung: CnH2n
nCnH2n = 0.15; mCnH2n = 7.7g --> M = 14n = 7.7/0.15 --> n = 11/3 ~ 3.67
Vi` 2 anken ke' tiep' --> C3H6 & C4H8
2Goi CT chung: CnH2n
nCnH2n = 0.15; mCnH2n = 7.7g --> M = 14n = 7.7/0.15 --> n = 11/3 ~ 3.67
Vi` 2 anken ke' tiep' --> C3H6 & C4H8
GOi x = nC4H8 --> nC3H6 = 0.15 - x
n = [4x + 3(0.15 - x)]/0.15 = 11/3 --> x = 0.1
--> %VC4H8 = 0.1/0.15 = 66.67%
2Goi CT chung: CnH2n
nCnH2n = 0.15; mCnH2n = 7.7g --> M = 14n = 7.7/0.15 --> n = 11/3 ~ 3.67
Vi` 2 anken ke' tiep' --> C3H6 & C4H8