Mg +2HCl=> MgCl2 + H2x 2x x xMgO + 2HCl=> MgCl2 + H2Oy 2y y yta luôn thấy nCl= 2 nO (oxit)họi nO=x => nCl=2x m chất rắn tăng= mCl pư vs oxit - mO (oxit) + mCl (pư vs Mg)<=> 28,5-8,8= 71y-16y + 71x=> 71x + 55y = 19,7 24x + 40 y = 8,8=> x= 0,2 y= 0,1=> %Mg = 54,545% % MgO= 45,455%bnHCl pư = 2x+2y= 2.0,2+2.0,1=0,6=> mdd HCl= $\frac{0,6.36,5.100}{14,6}$= 150 (g)cn MgCl2 = 0,2 + 0,1 = 0,3 mol=> m MgCl2 = 95.0,3=28,5 (g)mdd= m hh + mdd HCl - mH2 = 8,8 + 150- 0,2.2= 158,4 (g)=> C% MgCl2 = $\frac{28,5}{158,4}$.100%=17,99%
Mg +2HCl=> MgCl2 + H2x 2x x xMgO + 2HCl=> MgCl2 + H2Oy 2y y yta luôn thấy nCl= 2 nO (oxit)họi nO=x => nCl=2x m chất rắn tăng= mCl pư vs oxit - mO (oxit) + mCl (pư vs Mg)<=> 28,5-8,8= 71y-16y + 71x=> 71x + 55y = 19,7 24x + 40 y = 8,8=> x= 0,2 y= 0,1=> %Mg = 54,545% % MgO= 45,455%bnHCl pư = 2x+2y= 2.0,2+2.0,1=0,6=> mdd HCl= $\frac{0,6.36,5.100}{14,6}$= 150 (g)cn MgCl2 = 0,2 + 0,1 = 0,3 mol=> m MgCl2 = 95.0,3=28,5 (g)mdd= m hh + mdd HCl - mH2 = 8,8 + 150- (0,2+0,1).2= 158,2 (g)=> C% MgCl2 = $\frac{28,5}{158,2}$.100%=18,015%
Mg +2HCl=> MgCl2 + H2x 2x x xMgO + 2HCl=> MgCl2 + H2Oy 2y y yta luôn thấy nCl= 2 nO (oxit)họi nO=x => nCl=2x m chất rắn tăng= mCl pư vs oxit - mO (oxit) + mCl (pư vs Mg)<=> 28,5-8,8= 71y-16y + 71x=> 71x + 55y = 19,7 24x + 40 y = 8,8=> x= 0,2 y= 0,1=> %Mg = 54,545% % MgO= 45,455%bnHCl pư = 2x+2y= 2.0,2+2.0,1=0,6=> mdd HCl= $\frac{0,6.36,5.100}{14,6}$= 150 (g)cn MgCl2 = 0,2 + 0,1 = 0,3 mol=> m MgCl2 = 95.0,3=28,5 (g)mdd= m hh + mdd HCl - mH2 = 8,8 + 150- 0,2.2= 158,
4 (g)=> C% MgCl2 = $\frac{28,5}{158,
4}$.100%=1
7,
99%