Theo ĐLBTKL $\Rightarrow m_{O_{2}}=3,43-2,15=1,28\Rightarrow n_{O_{2}}=0,04$(mol)$\Rightarrow n_{O^{-2}}=0,08$Có $2H^{+}+O^{2-}_{}\rightarrow H_{2}O$ $0,16\leftarrow 0,08 $ (mol)$\Rightarrow n_{HCl}=n_{H^{+}}=0,16$$\Rightarrow V=\frac{0,16}{0,5}=0,32(l)$
Theo ĐLBTKL $\Rightarrow m_{O_{2}}=3,43-2,15=1,28\Rightarrow n_{O_{2}}=0,04$(mol)Có $2H^{+}+O^{2-}_{}\rightarrow H_{2}O$ $0,08\leftarrow 0,04 $ (mol)$\Rightarrow n_{HCl}=n_{H^{+}}=0,08$$\Rightarrow V=\frac{0,08}{0,5}=0,16(l)$
Theo ĐLBTKL $\Rightarrow m_{O_{2}}=3,43-2,15=1,28\Rightarrow n_{O_{2}}=0,04$(mol)
$\Rightarrow n_{O^{-2}}=0,08$Có $2H^{+}+O^{2-}_{}\rightarrow H_{2}O$ $0,
16\leftarrow 0,0
8 $ (mol)$\Rightarrow n_{HCl}=n_{H^{+}}=0,
16$$\Rightarrow V=\frac{0,
16}{0,5}=0,
32(l)$