$Fe_xO_y+2yHCl \rightarrow xFeCl_{\frac{2y}{x}}+yH_2O$thay vào rồi tính $n_{HCl}=\frac{52,14.1,05.10}{100.(35,5+1)}=0,15$$\Rightarrow \frac{56x+16y}{4}=\frac{0,15}{y}$$\Rightarrow \frac{x}{y}=\frac{2}{3}$$\Rightarrow Fe_2O_3$
$Fe_xO_y+2yHCl \rightarrow xFeCl
2_{\frac{y}{x}}+yH_2O$thay vào rồi tính $n_{HCl}=\frac{52,14.1,05.10}{100.(35,5+1)}=0,15$$\Rightarrow \frac{56x+16y}{4}=\frac{0,15}{y}$$\Rightarrow \frac{x}{y}=\frac{2}{3}$$\Rightarrow Fe_2O_3$