$Fe_{x}O_{y}+2yHCL\rightarrow Fe_{x}Cl_{2y/x}+yH_{2}O$$có : n_{HCl}=0.15\Rightarrow \frac{4}{56x+16y}=\frac{0.15}{2y}$$\Leftrightarrow8y=8.4x+2.4y\Leftrightarrow 8.4x=5.6y\Leftrightarrow \frac{x}{y}=\frac{2}{3} $$\Rightarrow Fe_{2}O_{3}$
$Fe_{x}O_{y}+2yHCL\rightarrow
xFeCl_{
\frac{2y
}{x
}}+yH_{2}O$$có : n_{HCl}=0.15\Rightarrow \frac{4}{56x+16y}=\frac{0.15}{2y}$$\Leftrightarrow8y=8.4x+2.4y\Leftrightarrow 8.4x=5.6y\Leftrightarrow \frac{x}{y}=\frac{2}{3} $$\Rightarrow Fe_{2}O_{3}$