lay hai lan pt duoi tru mot lan pt tren ta cox2+2−3y+2√y(x2+2)=0⇔1−3yx2+2+2√yx2+2=0=>y=x2+2 thay vao pt doi ta co$x^3+x^2+2x+3=0 =>x=........$ (minh ko co may tinh .tu lam nha)
lay hai lan pt duoi tru mot lan pt tren ta co
x2+2−3y+2√y(x2+2)=0⇔1−3yx2+2+2√yx2+2=0=>y=x2+2 thay vao pt doi ta co$x^3+x^2+
3x+3=0 =>x=
-1=>y=3$