4x2−13x+5+3x+1−−−−−√=0⇔−3x−1+3x+1−−−−−√+4x2−10x+6=0→ Δ=(4x−5)2Nên ta có 2 pt:(1) 4x2−11x+3=0⇒⎧⎩⎨⎪⎪⎪⎪⎪⎪x=11+73−−√8x=11−73−−√8(2) 4x2−15x+8=0⇒⎧⎩⎨⎪⎪⎪⎪⎪⎪x=15+97−−√8x=15−97−−√8
m,4x2−13x+5+3x+1−−−−−√=0⇔−3x−1+3x+1−−−−−√+4x2−10x+6=0→ Δ=(4x−5)2Nên ta có 2 pt:(1) 4x2−11x+3=0⇒⎧⎩⎨⎪⎪⎪⎪⎪⎪x=11+73−−√8x=11−73−−√8(2) 4x2−15x+8=0⇒⎧⎩⎨⎪⎪⎪⎪⎪⎪x=15+97−−√8x=15−97−−√8