⇔2√5x3+3x2+3x−2=x2+6x−1$\Leftrightarrow4(5x^3+3x^2+3x-2)=x^4+36x^2+1+12x^3-12x-2x^2⇔x4−8x3+22x2−24x+9=0\Leftrightarrow (x-3)^2(x-1)^2$the end
⇔2√5x3+3x2+3x−2=x2+6x−1$\Leftrightarrow4(5x^3+3x^2+3x-2)=x^4+3
4x^2+1+12x^3-12x-2x^2
⇔x4−8x3+22x2−24x+9=0\Leftrightarrow (x-3)^2(x-1)^2$the end