DK:.........$\frac{\sqrt{x-2}+\sqrt{x-1}(\sqrt{x-2}+1)}{2(\sqrt{x-2})^2+2-\sqrt{x-1}-3}\geq \frac{\sqrt{x-2}+1}{6}$$\frac{(\sqrt{x-2}+1)(\sqrt{x-1}+1)-1}{2(\sqrt{x-2}+1)^2-2(\sqrt{x-2}+1)-(\sqrt{x-1}+1)}\geq \frac{\sqrt{x-2}+1}{6}$phần còn lại tự làm nhé ^^
DK:.........$\frac{\sqrt{x-2}+\sqrt{x-1}(\sqrt{x-2}+1)}{2(\sqrt{x-2})^2+2-\sqrt{x-1}-3}\geq \frac{\sqrt{x-2}+1}{6}$$\frac{(\sqrt{x-2}+1)(\sqrt{x-1}+1)+1}{2(\sqrt{x-2}+1)^2-2(\sqrt{x-2}+1)-(\sqrt{x-1}+1)}\geq \frac{\sqrt{x-2}+1}{6}$phần còn lại tự làm nhé ^^
DK:.........$\frac{\sqrt{x-2}+\sqrt{x-1}(\sqrt{x-2}+1)}{2(\sqrt{x-2})^2+2-\sqrt{x-1}-3}\geq \frac{\sqrt{x-2}+1}{6}$$\frac{(\sqrt{x-2}+1)(\sqrt{x-1}+1)
-1}{2(\sqrt{x-2}+1)^2-2(\sqrt{x-2}+1)-(\sqrt{x-1}+1)}\geq \frac{\sqrt{x-2}+1}{6}$phần còn lại tự làm nhé ^^