trong 8,6 g XĐặt $n_{CH4}=x, n_{C2H4}=y, n_{C2H2}=z$$C2H4+Br2\rightarrow C2H4Br2$y y$C2H2+2Br2\rightarrow C2H2Br4$z 2z $\Rightarrow \begin{cases}16x+28y+26z=8,6 (1) \\ y+2z=\frac{48}{160} \end{cases}(2)$trong 0,6 mol hỗn hợp X$CH\equiv CH+2AgNO3+2NH3\rightarrow C2Ag2+NH4NO3$ $n_{C2Ag2}=0,15=n_{C2H2}=\frac{1}{4}n_{X}=\frac{1}{4}(x+y+z)\Rightarrow \frac{1}{4}+\frac{1}{4}+\frac{-3}{4}=0(3)$(1)(2)(3)$\Rightarrow x=0,2, y=o,1, z=0,1$ %$V_{CH4} =\frac{0,2}{0,4}\times 100=50$%
trong 8,6 g XĐặt $n_{CH4}=x, n_{C2H4}=y, n_{C2H2}=z$$C2H4+Br2\rightarrow C2H4Br2$y y$C2H2+2Br2\rightarrow C2H2Br4$z 2z $\Rightarrow \begin{cases}16x+28y+26z=8,6 (1) \\ y+2z=\frac{48}{160} \end{cases}(2)$trong 0,6 mol hỗn hợp X$CH\equiv CH+2AgNO3+2NH3\rightarrow C2Ag2+NH4NO3$ $n_{C2Ag2}=0,15=n_{C2H2}=\frac{1}{4}n_{X}=\frac{1}{4}(x+y+z)\Rightarrow \frac{1}{4}+\frac{1}{4}+\frac{-3}{4}=0(3)$(1)(2)(3)$\Rightarrow x=0,2, y=o,1, z=0,1$ %$V_{CH4} 33,33$%
trong 8,6 g XĐặt $n_{CH4}=x, n_{C2H4}=y, n_{C2H2}=z$$C2H4+Br2\rightarrow C2H4Br2$y y$C2H2+2Br2\rightarrow C2H2Br4$z 2z $\Rightarrow \begin{cases}16x+28y+26z=8,6 (1) \\ y+2z=\frac{48}{160} \end{cases}(2)$trong 0,6 mol hỗn hợp X$CH\equiv CH+2AgNO3+2NH3\rightarrow C2Ag2+NH4NO3$ $n_{C2Ag2}=0,15=n_{C2H2}=\frac{1}{4}n_{X}=\frac{1}{4}(x+y+z)\Rightarrow \frac{1}{4}+\frac{1}{4}+\frac{-3}{4}=0(3)$(1)(2)(3)$\Rightarrow x=0,2, y=o,1, z=0,1$ %$V_{CH4}
=\frac{0,
2}{0,4}\times 100=50$%