so mol CO2=so mol ket tua=0,2khoi luong giam di=Klg H2O+KLg CO2=24,3$\Rightarrow so mol H_2O$=$\frac{24,3-0,2\times44 }{18}$=0,35$n_H$=0,7so mol N trong hop chat=($34,72\div 22,4)\times 2-4\times (0,2\times 2+0,35)$=0,1$\Rightarrow $C:H:N=0,2:0,7:0,1=2:7:1do dx/o2<2$\Rightarrow $Cong thuc:C2H7N
so mol CO2=so mol ket tua=0,2khoi luong giam di=Klg
ket tua-(Klg H2O+KLg CO2
)=24,3$\Rightarrow so mol H_2O$=$\frac{
39,4-24,3-0,2\times44 }{18}$=0,35$n_H$=0,7so mol N trong hop chat=($34,72\div 22,4)\times 2-4\times (0,2\times 2+0,35)$=0,1$\Rightarrow $C:H:N=0,2:0,7:0,1=2:7:1do dx/o2<2$\Rightarrow $Cong thuc:C2H7N