khoi luong mol trung binh cua 2 anken la 1,35.28=37,8\rightarrow n=2,7\Rightarrow2 anken la C2H4 va C3H6,tu KLM=37,8\Rightarrow ti le mol C2H2 :C3H6=3:7(so do duong cheo) goi mol C2H2=3x,mol C3H6=7x, ancol bac 2 la CH3CH(OH)CH3 co m=50\Rightarrow mol=\frac{5}{6}\Rightarrow mol CH3CH2CH2OH=7x-\frac{5}{6}\Rightarrow KL cua CH3CH2OH v CH3CH2CH2OH=43 tu do biet x
khoi luong mol trung binh cua 2 anken la 1,35.28=37,8
$\rightarrow n=2,7\Rightarrow2 anken la C2H4 va C3H6,tu KLM=37,8\Rightarrow
$ ti le mol C2H2 :C3H6=3:7(so do duong cheo) goi mol C2H2=3x,mol C3H6=7x, ancol bac 2 la CH3CH(OH)CH3 co m=50
$\Rightarrow mol=\frac{5}{6}\Rightarrow
$ mol CH3CH2CH2OH=7x-
$\frac{5}{6}\Rightarrow
$ KL cua CH3CH2OH v CH3CH2CH2OH=43 tu do biet x