nN0=0,1hh B co kl lon hon do O2 phan ung voi Fe mO =mhhB-mFeban dau=12-mFe0 -3e _Fe+3 nenhan=3nFe2O0 +2*2e_2O-2 N+5 +3e _N+2 (NO)nenhuong =nenhan3nFe=4nO2 +3nNO32*3m\56=56*4(12-m)\32+3*0,1m=10.08
bai5 nN0=0,1
hh B co kl lon hon do O2 phan ung voi Fe mO =mhhB-mFeban dau=12-mFe0 -3e _Fe+3 nenhan=3nFe2O0 +2*2e_2O-2 N+5 +3e _N+2 (NO)nenhuong =nenhan3nFe=4nO2 +3nNO32*3m\56=56*4(12-m)\32+3*0,1m=10.08