1 mt=ms=8.8ns=2nt=>ns=0.9*0.2*2=0.36(vi 1molC3H8cho ra 1molCH4(C3H6)va 1molC2H4(H2) )nspu=0.2-0.9*0.2+0.36=0.38M=m/n=440/19=23.162 caanfn co phai la cầndot chay Y thi cung nhu dot chay C3H8C3H8+5O2-->3CO2+4H2O0.2 1VO2=22.4Vkk=22.4/0.2=112l3 C2H4vaC3H6deu td voi Brom%CH4+%H2=100%CH4*16+%H2*2=14.6*100=>%CH4=90%;%H2=10%neu khong cho tinh theo cach tren thi gia su roi tinh theo nhu he Pt tren