nFeCl2= 31,75/127=0.25 ap dung dinh luat bao toan nguyen tu nguyen to Cl:2HCl-->FeCl2 0.5 0.25dat so mol cac chat lan luoc x,y,zx+y+z=0.25pp duong cheox/z=1/256x+72y+116z=21.6x=0.05;y=0.1;z=0.1C2 ne u lop * chac chua hoc cach tren Fe+2HCl-->FeCl2+H2x 2x x xFeO+2HCl-->FeCl2+H2Oy 2y yFeCO3+2HCl-->FeCl2+H2O+CO2z 2z z znHCl=2x+2y+2z=2(x+y+z)=2nFeCl2=0.5molx+y+z=0.252x+44z=(x+z)*30=>-28x+14z=056x+72y+116z=21.6x=0.05y=0.1z=0.1=>%mFe=12.963%%mFeO=33.333%%mFeCO3=53.704%,
nFeCl2= 31,75/127=0.25 ap dung dinh luat bao toan nguyen tu nguyen to Cl:2HCl-->FeCl2 0.5 0.25HCl0.5M chu khong phai 0.5% dau lon roi doV=n/CM=1litdat so mol cac chat lan luoc x,y,zx+y+z=0.25pp duong cheox/z=1/256x+72y+116z=21.6x=0.05;y=0.1;z=0.1C2 ne u lop * chac chua hoc cach tren Fe+2HCl-->FeCl2+H2x 2x x xFeO+2HCl-->FeCl2+H2Oy 2y yFeCO3+2HCl-->FeCl2+H2O+CO2z 2z z znHCl=2x+2y+2z=2(x+y+z)=2nFeCl2=0.5molx+y+z=0.252x+44z=(x+z)*30=>-28x+14z=056x+72y+116z=21.6x=0.05y=0.1z=0.1=>%mFe=12.963%%mFeO=33.333%%mFeCO3=53.704%,
nFeCl2= 31,75/127=0.25 ap dung dinh luat bao toan nguyen tu nguyen to Cl:2HCl-->FeCl2 0.5 0.25dat so mol cac chat lan luoc x,y,zx+y+z=0.25pp duong cheox/z=1/256x+72y+116z=21.6x=0.05;y=0.1;z=0.1C2 ne u lop * chac chua hoc cach tren Fe+2HCl-->FeCl2+H2x 2x x xFeO+2HCl-->FeCl2+H2Oy 2y yFeCO3+2HCl-->FeCl2+H2O+CO2z 2z z znHCl=2x+2y+2z=2(x+y+z)=2nFeCl2=0.5molx+y+z=0.252x+44z=(x+z)*30=>-28x+14z=056x+72y+116z=21.6x=0.05y=0.1z=0.1=>%mFe=12.963%%mFeO=33.333%%mFeCO3=53.704%,