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$X+nH_{2}O\rightarrow X(OH)_{n}+\frac{n}{2}H_{2}$ $\frac{11,5}{X}$ $\frac{11,5}{X}$ $\frac{11,5.n}{X.2}$
$m_{X(OH)n}=\frac{11,5}{X}.(X+17n)$ $m_{H_{2}}=\frac{11,5}{X}.\frac{n}{2}.2=\frac{11,5}{X}n$ $m_{dd}=11,5+189- \frac{11,5}{X}n=200,5- \frac{11,5}{X}n$ C%$=\frac{\frac{11,5}{X}.(X+17n)}{200,5- \frac{11,5}{X}n}.100=10$ Thu gọn X theo n ta được: $X=23n$ Với n =1 X =23(Na)
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