ĐK: x \leq \frac{6}{5}Đặt \sqrt[3]{3x-2}=a, \sqrt{6-5x}=b (b \geq 0)Ta có hệ: {2a+3b=85a3+3a2=8\Leftrightarrow {b=8−2a345a3+12a2−96a+120=0\Leftrightarrow {a=−2b=4...Đs: x=-2
ĐK: x $\leq$ $\frac{6}{5}$ Đặt $\sqrt[3]{3x-2}$=a, $\sqrt{6-5x}$=b (b $\geq$ 0)Ta có hệ: ${2a+3b=85a3+3a2=8$$\Leftrightarrow$ ${b=8−2a345a3+12a2−96a+120=0$$\Leftrightarrow$ ${a=−2b=4$...Đs: x=-2