1. $C5H12$$CH3CH2CH2CH2CH3$
$CH3CH(CH3)CH2CH3$
$CH3C(CH3)2CH3$
=>Chọn B
2. m$C2H2$ =2,6.1000=2600g
=>n$C2H2$ =100 mol
Mà đốt cháy 1 mol cần 1320kJ
=>đốt cháy 100 mol $C2H2$ cần 132000kJ
3.n$H_2O$ =18,9/18=1,05 mol
nankan=n$H2O$ - n$CO2$
=>n$CO2$ =1,05-0,3=0,75 mol
Mà $Ca(OH)2$ dư=>n$CO_2$ =n$CaCO3$ =0,75 mol
=>mktủa=0,75.100=75g
4. $C2H2$ + 5/2$O2$ => 2$CO2$ + $H2O$
n$CO2$ =3/100=0,03 mol=>n$C2H2$ =0,03/2=0,015 mol
5. $(C6H10O5)n$ +n $H_2O$ =>n$C6H12O6$
2000/n mol<=2000 mol
=>2000/n=0,2=>n=10000