n$H2$=11,2/22,4=0,5 mol
n$H2O$=13,5/18=0,75 mol
$CH2=CH-CHO$ + $H2$ => $CH3CH2CH2OH$
$Na$ + $H2O$ => $NaOH$ + ½ $H2$
0,75 mol<=0,75 mol =>0,375 mol
$CH3CH2CH2OH$ + $Na$ =>$CH3CH2CH2ONa$ +½ $H2$
0,25 mol<= 0,25 mol<= 0,25 mol<= 0,125 mol
n$CH3CH2CH2ONa$=0,25 mol=n$CH3CH2CH2OH$
=>m$CH3CH2CH2OH$=60.0,25=15g
C% của X=15/(15+13,5).100%=52,63% chọn A