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Ta có:
$\left\{ \begin{array}{l} 2x^2-8xy^2-xy+4y^3=0\\ 16x^3+2x-8y^2+5=0 \end{array} \right.$
$\Leftrightarrow \left\{ \begin{array}{l} (x-4y^2)(2x-y)=0\\16x^3+2x-8y^2+5=0 \end{array} \right.$
$\Leftrightarrow \left[ \begin{array}{l} \left\{ \begin{array}{l} x=4y^2\\ 1024x^6+8y^2-8y^2+5=0 \end{array} \right.\\\left\{ \begin{array}{l} 2x=y\\ 2y^3+y-8y^2+5=0 \end{array} \right. \end{array} \right.$
$\Leftrightarrow \left[\begin{array}{l} \left\{ \begin{array}{l} x=\frac{1}{2}\\ y=1 \end{array} \right.\\\left\{ \begin{array}{l} x=\frac{1}{4}(3-\sqrt{19})\\ y=\frac{1}{2}(3-\sqrt{19}) \end{array} \right.\\\left\{ \begin{array}{l} x=\frac{1}{4}(3+\sqrt{19})\\ y=\frac{1}{2}(3+\sqrt{19}) \end{array} \right. \end{array} \right.$
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