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Đặt $n_{NaCl}=x n_{NaBr}=y n_{NaI}=z$
TN1:$\Rightarrow 58,5x+103y+150z=1,732$ (1)
TN2:
$2 NaI+Br_{2}\rightarrow 2NaBr+I_{2}$
y y
$58,5x+103y+103z=1,685$ (2)
TN2
$2NaBr+Cl_{2}\rightarrow2 NaCl+Br_{2}$
y y
$2NaI+Cl_{2}\rightarrow2 NaCl+I_{2}$
z z
$\Rightarrow 58,5x+58,5y+58,5x=1,4625$ (3)
Giải hệ(1),(2),(3)đượcx=0,02, y=0,004, x=0,001
$\Rightarrow C_{M}NaCl=\frac{0,02}{0,02}=1M$
$C_{M}NaBr=\frac{0,04}{0,02}=2M$
$C_{M}NaI=\frac{0,001}{0,02}=0,05M$
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Trả lời 18-01-13 08:42 PM
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