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$X:\begin{cases}NaCl:2x mol \\NaBr:2y mol\\NaI:2y mol \end{cases}$
$P_1:$
$2NaBr+Cl_2\rightarrow 2NaCl+Br_2$
$y y$
$2NaI+Cl_2\rightarrow 2NaCl+I_2$
$y y$
$\Rightarrow 58,5(x+y+y)=5,85\Rightarrow x+2y=0,1 mol (1)$
$P_2:$
$NaCl+AgNO_3\rightarrow NaNO_3+AgCl\downarrow$
$x x$
$NaBr+AgNO_3\rightarrow NaNO_3+AgBr\downarrow$
$y y$
$NaI+AgNO_3\rightarrow NaNO_3+AgI\downarrow$
$y y$
$\Rightarrow 143,5x+188y+235y=17,75 (2)$
$\begin{cases}(1) \\(2) \end{cases}\Rightarrow \begin{cases}x=0,05 mol \\ y=0,025 mol \end{cases}\Rightarrow \begin{cases}m=2(58,5.0,05+103.0,025+150.0,025)=18,5 gam \\\%NaCl=\frac{58,5.0,1.100}{18,5}=31,62\%\\\%NaBr=27,84\%\\\%NaI=40,54\% \end{cases}$
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Trả lời 14-03-13 12:24 AM
viet130480
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