$C_\overline{x}H_{2\overline{x}+2}O+(1,5\overline{x}-0,5)O_2\rightarrow \overline{x}CO_2+(\overline{x}+1)H_2O $$n_{O_2}=0,45 mol\Rightarrow 1,5\overline{x}-0,5=2,25 \Rightarrow \overline{x} =1,833 $
$\Rightarrow \begin{cases}CH_3OH \\CH_3CH_2OH \end{cases}$