$a)2C_2H_5OH+2Na\rightarrow 2C_2H_5ONa+H_2\uparrow$
$2C_6H_5OH+2Na\rightarrow C_6H_5ONa+H_2\uparrow$
$b)\begin{cases}C_2H_5OH:x mol \\C_6H_5OH:y mol \end{cases}\Rightarrow \begin{cases}x+y=\frac{3,36}{2.22,4} \\y=\frac{19,86}{331} \end{cases}\Rightarrow \begin{cases}x=0,015 mol \\ y=0,06 mol \end{cases}$
$\Rightarrow \begin{cases}\%C_2H_5OH=\frac{0,015.46.100}{0,015.46+0,06.88}=11,56\% \\ \%C_6H_5OH=88,44\% \end{cases}$