$2Al+6HCl\rightarrow 2AlCl_3+3H_2\uparrow$ $\frac{m}{27} \frac{m}{27}$
$2Na+2H_2O\rightarrow 2NaOH+H_2\uparrow$
$\frac{m}{23} \frac{m}{23}$
$3NaOH+AlCl_3\rightarrow Al(OH)_3+3NaCl$
$\frac{m}{23} \frac{m}{69} \frac{m}{69}$
$\Rightarrow \frac{m}{69}=\frac{3,51}{78}\Rightarrow m=3,105 gam$
$\Rightarrow m_A=3,105+\frac{3,105.3.36,5.100}{27.18,25}-\frac{3,105.1,5.2}{27}=71,76 gam$