$\Rightarrow M_X=\frac{0,56}{0,01n}\Rightarrow M_X=\frac{56}{n}\Rightarrow X:C_4H_8$$C_\overline{n}H_{2\overline{n} +2}+(1,5\overline{n}+0,5)O_2\rightarrow \overline{n}CO_2+(\overline{n}+1)H_2O$
$1 (1,5\overline{n}+0,5 )$
$0,025 0,14 mol$
$\Rightarrow \overline{n}=3,4 \Rightarrow \begin{cases}Y:C_3H_8 \\Z:C_4H_{10} \end{cases}\Rightarrow a=m_{CO_2}+m_{H_2O}=5,72 gam$