$\begin{cases}HCl:0,15 mol \\Na_2CO_3:x mol\\NaHCO_3:y mol \end{cases}\Rightarrow \begin{cases}0,15-x=\frac{1,008}{22,4} \\(x+ y)-(0,15-x)=\frac{29,55}{197} \end{cases}\Rightarrow \begin{cases}x=0,105 mol \\ y=0,09 mol \end{cases}$$\Rightarrow \begin{cases}C_M(Na_2CO_3)=0,21 M \\C_M(NaHCO_3)=0,18 M \end{cases}\Rightarrow Chon:C$