$m_2+HCl\rightarrow H_2\Rightarrow m_2:\begin{cases}Al:x mol \\Cu:y mol\\Ag:z mol \end{cases}\Rightarrow \begin{cases}x=\frac{0,336}{1,5.22,4} \\ y=n_{Cu(NO_3)_2}\\z=n_{AgNO_3} \end{cases}\Rightarrow \begin{cases}x=0,01 mol \\ y=0,03 mol\\z=0,03 mol \end{cases}$$\Rightarrow m_2=5,43 gam$
$\Rightarrow m_1=27(x+\frac{2y}{3}+\frac{z}{3})=1,08 gam$