$*)X:\begin{cases}n_{O_2}=x mol \\n_{O_3}=y mol \end{cases}\Rightarrow \frac{32x+48y}{x+y}=2.22\Rightarrow \frac{x}{y}=\frac{1}{3}\Rightarrow \frac{n_{O_2}}{n_{O_3}}=\frac{1}{3}$$*)Y:\begin{cases}n_{CH_5N}=a mol \\n_{C_2H_7N}=b mol \end{cases}\Rightarrow \frac{31a+45b}{a+b}=2.17,833\Rightarrow \frac{a}{b}=\frac{2}{1}\Rightarrow \frac{n_{CH_5N}}{n_{C_2H_7N}}=\frac{2}{1}$
$2CH_5N+9[O]\rightarrow 2CO_2+5H_2O+N_2$
$C_2H_7N+7,5[O]\rightarrow 2CO_2+3,5H_2O+0,5N_2$
$\Rightarrow \begin{cases}\frac{V_1}{V_{[O]}}=\frac{2+1}{9+7,5} \\\frac{V_{[O]}}{V_2}=\frac{2.1+3.3}{1+3} \end{cases}\Rightarrow \frac{V_1}{V_2}=\frac{(2+1)(2.1+3.3)}{(9+7,5)(1+3)}=\frac{1}{2}$