\begin{cases}CH_4:x mol \\C_3H_6:y mol\\C_2H_2:z mol \end{cases} \begin{cases}16x+42y+26z=10 \\ y+2z=0,3 mol \\tx+ty+tz=0,6 mol\\tz=0,15 mol\end{cases}$\Rightarrow \begin{cases}16x+42y+26z=10 \\y+2z=0,3\\x+y=3z \end{cases}\Rightarrow \begin{cases}x=0,2 mol \\ y=0,1 mol\\z=0,1 mol \end{cases}$
$\Rightarrow \%m_{CH_4}=\frac{100(16.0,2)}{10}=32\%\Rightarrow Chon:C$