$\overline{R}CH_2OH+CuO \rightarrow \overline{R}CHO+Cu+H_2O $$n_{\overline{R}CH_2OH }=n_{CuO}=\frac{4,8}{80}=0,06 mol\Rightarrow M_{\overline{R}CH_2OH} =\frac{2,2}{0,06}\Rightarrow M_{\overline{R} }=5,667$
$\Rightarrow \begin{cases}HCHO:x mol \\ RCHO:y mol \end{cases}\Rightarrow \begin{cases}x+y=0,06 \\ 4x+2y=\frac{23,76}{108} \end{cases}\Rightarrow \begin{cases}x=0,05 mol \\ y=0,01 mol \end{cases}$
$\Rightarrow m_{RCH_2OH}=2,2-0,05.32=0,6 gam\Rightarrow M_{RCH_2OH}=\frac{0,6}{0,01}=60$
$\Rightarrow C_2H_5CH_2OH\Rightarrow \begin{cases}CH_3OH \\ CH_3CH_2CH_2OH\end{cases}$