$nO=\frac{11,62-8,42}{16}=0,2$Ta cos $nHNO3=2nO+4nNO=0,64$
co le ban biet CT cho KL tac dung HNO3 co
$nHNO_3=4nNO+12nN_2+10nN_2O+10nNH_4NO_3$
cai cho hon hop kia to coi nhu la co kim loai va cac oxit cao nhat
$R_2O_n\rightarrow R(NO_3)n$
de thay $nNO_3=2nO$ con vao co ct tren nhe