CTTQ NaxCyOz ADCT
nNa = \frac{9,2}{2,3} = 0,4 mol
nC=\frac{2,4}{12} = 0,2 mol
nO= \frac{9,6}{16} = 0,6 mol
x = \frac{nNa}{nNaxCyOz} = \frac{0,4}{0,2} = 2
y = \frac{nC}{nNaxCyOz} = \frac{0,2}{0,2} =1
z = \frac{nO}{nNaxCyOz} = \frac{0,6}{0,2} = 3
\Rightarrow CTPT Na2CO3