Sau phan ung $\begin{cases}BaSO_4=0,03 mol \\ Na_2SO_4=0,185 mol\rightarrow Na_2ZnO_2=0,025\end{cases}$Dat $\begin{cases}Mg=a mol\\ Zn=bmol \end{cases}$
nung ket tua ta co $MgO=a mol ZnO=b-0,025 BaSO_4=0,03$
$\rightarrow ..$
m ra so mol xau qua chac nham dau rui