$CH_3COOC_2H_5+NaOH\rightarrow CH_3COONa+C_2H_5OH$
$CH_3COOC_6H_5+2NaOH\rightarrow CH_3COONa+C_6H_5ONa+H_2O$
$*)\begin{cases}CH_3COOC_2H_5:x mol \\ CH_3COOC_6H_5:x mol \end{cases}\Rightarrow x(88+136)=4,48\Rightarrow x=0,02 mol$$*)n_{NaOH}=0,08 mol$
$\Rightarrow X:\begin{cases}CH_3COONa:0,04 mol \\ C_6H_5ONa:0,02 mol \\NaOH:0,02 mol \end{cases}$
$\Rightarrow m_X=0,04.82+0,02.116+0,02.40=6,4 gam$