c1sau khi tat ca cac phan ung xay ra thi Z chi co hidrocacon no
Mz=16
1 chat phai la H2 con chat kia la C2H6 va Ch4 ( vi xuat phat ban dau chi gom C2H2 thoi )
Dung bao toan khoi luong tim mz=10.28 - 1.64 = 8.64
goi so mol H2 , C2H6 la a va b
Mz=16 ( trung voi M ch4) nen dung duong cheo tim la a=b
nz=m(z)/M(z)=0.54
a+b+0.3=0.54
>>a=b=0.12
>> so mol h2 phan ung la 0.4-0.12=0.28mol
cau2
goi so mol cua C2H2 trong Y la x
C2H4 y
dung bao toan nguyen to ta co
2x + 2y + 0.12=0.24
2x +4y +0.4 = 0.6
tim x=0.02 va y=0.04