câu 3bạn đầu
CO2+CA(OH)2=>CACO3+H2O
CO+CUO=>CU +CO2
nCO=nCU=6.35/64=0.1
nCO2=nCACO3=0.1
nN2=0.45-0.2=0.25
=>%VN2=55.56% %V CO2=%V CO=22.22%
sau
CO+CUO=>CU+CO2
0.1......................0.1
CO2+CA(0H)2=>CACO3+H2O
0.2.........................0.2
=>mCACO3=0.2*100=20g