Gọi nFe là a, nMg là blập hpt:
(e) 2a+ 2b= (6.72/22.4) *2
(m) 56a + 24b = 13.6
=> a= 0.2 mol, b= 0.1 mol
%Fe =0.2*56/13.6= 82.35% => %Mg = 13.65%
Cm Fe = 0.2/0.2 = 1 M
Cm Mg = 0.1/0.2 = 0.5 M
b) (e) 0.2*3 + 0.1*2 = nSO4*1 => n= 0.8 mol => v= 0.8*22.4 = 17.92 l