nFeCl2= 31,75/127=0.25 ap dung dinh luat bao toan nguyen tu nguyen to Cl:
2HCl-->FeCl2
0.5 0.25
dat so mol cac chat lan luoc x,y,z
x+y+z=0.25
pp duong cheo
x/z=1/2
56x+72y+116z=21.6
x=0.05;y=0.1;z=0.1
C2 ne u lop * chac chua hoc cach tren
Fe+2HCl-->FeCl2+H2
x 2x x x
FeO+2HCl-->FeCl2+H2O
y 2y y
FeCO3+2HCl-->FeCl2+H2O+CO2
z 2z z z
nHCl=2x+2y+2z=2(x+y+z)=2nFeCl2=0.5mol
x+y+z=0.25
2x+44z=(x+z)*30=>-28x+14z=0
56x+72y+116z=21.6
x=0.05
y=0.1
z=0.1
=>%mFe=12.963%
%mFeO=33.333%
%mFeCO3=53.704%,