1. nH+ =0,4x50/1000 =0,02(mol)nOH- =0.5x50/1000 =0.025(mol)ta có nOH- dư=0,025-0,02=0.005 (mol)[ OH-] = 0.005/0.1=0.05(mol)pOH=-lg[OH-] =-lg 0.05= 1.3pH=14-1.3=12,7
1. nH+ =0,4x50/1000 =0,02(mol)nOH- =0.5x50/1000 =0.025(mol)ta có nOH- dư=0,025-0,02=0.005 (mol)[ OH-] = 0.005/0.1=0.05(mol)pOH=-lg[OH-] =-lg 0.05= 1.3pH=14-1.3=12,7caau2 nOH- =0,6x(0,01+0,02x2) =0,03 nH+ =0,4x(0,02+0,02x2) =0,024(mol)nOH- dư=0,03-0,024=0.006(mol)[ OH-] =0.006/1=0,006M pOH=2,22 -------->pH=14-2.22=11,78có gì sai xót thông cảm nha ^^