$\begin{cases}C_2H_5OH:(x+y) mol \\C_2H_5COOH:x mol\\CH_3CHO:y mol\\n_{H_2O}=0,17 mol\\n_{CO_2}=0,14 mol \end{cases}\Rightarrow \begin{cases}x+y=0,17-0,14 \\2(x+y)+3x+2y=0,14 \end{cases}\Rightarrow \begin{cases}x=0,02 mol \\ y=0,01 mol \end{cases}$$\Rightarrow m=3,3 gam$
$\Rightarrow 13,2 gam:\begin{cases}n_{C_2H_5COOH}=\frac{13,2.0,02}{3,3}=0,08 mol \\n_{CH_3CHO}=...=0,04 mol\\n_{C_2H_5OH}=0,12 mol \end{cases}$
$\Rightarrow n_{Ag}=2n_{CH_3CHO}=0,08 mol\Rightarrow p=8,64 gam$