$1)$$2Al+3H_2SO_4\rightarrow Al_2(SO_4)_3+1,5H_2\uparrow$
$x 1,5x 1,5x$
$Zn+H_2SO_4\rightarrow ZnSO_4+H_2\uparrow$
$y y y$
$\Rightarrow \begin{cases}27x+65y=3,68 \\1,5x+y=\frac{2,24}{22,4} \end{cases}\Rightarrow \begin{cases}x=0,04 mol \\ y=0,04 mol \end{cases}$
$\Rightarrow n_{H_2SO_4}=0,1 mol\Rightarrow m_{dd H_2SO_4}=98 gam$
$\Rightarrow m_{dd}=3,68+98-2.0,1=101,48$