cau nay kho thiet day!!!!!!!!!!!!!!!!!!!!

Question

cho hon hop gom bot Cu, $Cu_2$O,CuO voi dung dich axit sunfuric loang thay khoi luongkim loai con lai sau phan ung bang $\frac{1}{4}$khoi luong hon hop ban dau.mat khac dun nong hh tren voi dung dich axit HCl dac thay 85% khoi luong hon hop tac dung.tinh luong hon hop can de dieu che 42,5 gam dong

viet130480 · Answer 1 · 7/3/2013 9:06:06 PM

Bình chọn tăng 0 Bình chọn giảm

$2Cu_2O+2H_2SO_4\rightarrow 2CuSO_4+2Cu+2H_2O$

$CuO+H_2SO_4\rightarrow CuSO_4+H_2O$

$Cu_2O+2HCl\rightarrow Cu_2Cl_2+H_2O$

$CuO+2HCl\rightarrow CuCl_2+H_2O$

$\begin{cases}n_{Cu}=x mol \\ n_{Cu_2O}=y mol\\n_{CuO}=z mol \end{cases}$

$\Rightarrow \begin{cases}64(x+y)=\frac{64x+144y+80z}{4}=\frac{m}{4} \\ 64x=\frac{(100-85)(64x+144y+80z)}{100}=\frac{3m}{20}\end{cases}\Rightarrow ...$

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Sửa 03-07-13 09:06 PM