$\Delta H^o = -110,525 – 241,818+393,509 -0=+41,166 kJ/mol$
$\Delta S^o = 197,665+188,716-213,66 -130,575=42,146 J.mol^{-1}.K^{-1}$
$\Delta G^o = \Delta H^o-T\Delta S^o$
$\Delta G^o=41,166-298.0,042146=+28,6064 kJ/mol$
$lg K_p=-\frac{\Delta G^o}{2,303RT}=\frac{28,6064}{2,303.8,314.10^{-3}.298}=-5,0135$
$K_p=9,7.10^{-6}$